NEET 2018 PRACTISE PAPER PHYSICAL CHEMISTRY
NEET 2018 PRACTISE PAPER-THERMO,EQUILIBRIUM,BONDING AND
STATE OF MATTER BY DR SUDHIR TOMAR
Q1.How are bond length and
bond energies related?
A)The higher the
bond energy, the longer the bond length
B)They are not
related
C)The higher the
bond energy, the shorter the bond length
D)The lower the
bond energy, the shorter the bond length
Q2.Which type of bonding would be expected
between S and Cl?
A)Polyionic B)Polar covalent C)Ionic D)Non-polar covalent
Q3. The
molecule having one unpaired electron is:
A)CO B)CN-
C)NO2 D)O
Q4. The ion
that isoelectronic with CO is
A) N2+ B)O2-
C)O2+ D)CN-
Q5. Molecular structure of SF6 is
A. linear
B. tetrahedral
C. hexagonal
D. octahedral
Q6. In
Al2Cl6, number of electron pairs donated by each Chloride
ion are
A. 1
B. 2
C. 3
D. 4
Answer B
Q7. Number of bonding pairs of electrons in
water H2O is
A. 1
B. 2
C. 3
D. 4
Answer B
Q8. Which
statement is incorrect?
A. boiling point is
independent of number of contact points
B. boiling point
depends upon number of electrons
C. boiling point
depends upon number of protons
D. boiling point is
dependent on number of neutrons
Q9. PH
of buffer solution depends upon concentration of
A. acid (H+-)
B. conjugate base (-OH-)
C. salt
D. both A and B
Answer D
Q10. Carminic
acid gives purple color with
A. acids (H+-)
B. alkalis (-OH-)
C. weak acids (H+-)
D. all of them
Answer B
Q11. PH
can be kept constant with help of
A. saturated solution
B. unsaturated solution
C. buffer solution
D. super saturated
solution
Answer C
Q12. In
an unsaturated solution, concentration of each ion of sparingly soluble salt at
298k tells us the
A. solubility product
B. solubility reactant
C. dynamic equilibrium
D. solubility
equilibrium
Answer A
Q13.. System
of reaction in which no reactant leaves reaction mixture is termed as
A. open system
B. closed system
C. semi-open system
D. partially closed system
Answer B
Q14. On
description of proton, new classification of acid and base was given by
A.
J.bronsted
B. T.lowry
C. J.Dalton
D. both A and B
Answer D
Q15. A
substance which neutralizes a base is called
A. acid
B. alkali
C. alkaloid
D. halogen
Answer A
Q16. Reactions
in which products cannot turn back into reactants are termed as
A. irreversible
reactions
B. reversible reactions
C. equilibrium
reactions
D. redox reactions
Answer A
Q17. Real
gases do not react as expected
A. ideal gas
B. noble gas
C. non-ideal gas
D. inert gas
Answer A
Q18. Force
of attraction and repulsion in gaseous molecule is
A. present
B. absent
C. slight
D. huge
Answer B
Q19. Silicon
D. oxide which is found in mineral quartz is very similar to
A. graphite
B. diamond
C. iron
D. copper
Answer B
Q20. Metal
which can be melted even by warmth of human palm is
A. gallium
B. indium
C. aluminum
D. tungsten
Answer A
Q21. Volume
occupied by 0.5 mole of carbon dioxide at a pressure of 150kPa and at
temperature of 19 °C will be
A. 8.09 dm3
B. 8.89 dm3
C. 9.09 dm3
D. 8.13 dm3
Answer A
Q22. Standard
enthalpy change of combustion occurs when 1 mol of substance is burnt in excess
of
A. nitrogen
B. oxygen
C. carbon dioxide
D. helium
Answer B
Q23. Enthalpy
changes which cannot be found by calorimeter can be found by help of
A. Newton's Law
B. Hess's Law
C. Krebs's Law
D. Ohm's Law
Answer B
Q24. Amount
of energy required to break a specific covalent bond is called
A. bond dissociation
energy
B. bond energy
C. bond enthalpy
D. All of Above
Answer D
Q25. Exothermic
enthalpy changes are shown as
A. negative values
B. positive values
C. neutral
D. constant
Answer A
Q26. Change
in enthalpy when 1 mol of compound is formed under standard conditions is
called
A. reaction
B. formation
C. combustion
D. neutralization
Answer B
Q27. Many
ionic compounds have some covalent ability due to
A. ion polarization
B. charge polarization
C. proton polarization
D. electron polarization
Answer A
Q28. Ionic
radius of cation will be smaller and more efficient in polarizing
A. carbonate ion
B. carbonate molecule
C. hydrogen ion
D. water
Answer A
Q29. Lithium
Fluoride
A. lesser
B. greater
C. same
D. never known
Answer A
Q30. Degree
of polarization depends on
A. charge density of
cations
B. polarisability
C. charge density of
anions
D. both A and B
Answer D
Q31. Isostructural
species are those which have the same shape and hybridisation. Among the given
species identify the isostructural pairs.
A. [NF3 and BF3 ] B. [BF4 – and NH4 + ]
C. [BCl3 and BrCl3 ] D. [NH3 and NO3
– ]
Q32. The types of
hybrid orbitals of nitrogen in NO2 + , NO3 –
and NH4 + respectively are expected to be
A. sp, sp3
and sp2 B. sp, sp2 and sp3
C. sp2 ,
sp and sp3 D. sp2 , sp3
and sp
Q33. Hydrogen bonds
are formed in many compounds e.g., H2O, HF, NH3 . The
boiling point of such compounds depends to a large extent on the strength of
hydrogen bond and the number of hydrogen bonds. The correct decreasing order of
the boiling points of above compounds is :
A. HF > H2O > NH3 B. H2O >
HF > NH3
C. NH3 > HF > H2O D. NH3 > H2O
> HF
Q34. In PO4
3–
ion the formal charge on the oxygen atom of P–O bond is
A. + 1
B. – 1
C. – 0.75 D. +
0.75
Q35. In NO3
–
ion, the number of bond pairs and lone pairs of electrons on nitrogen atom are
A. 2, 2 B. 3, 1
C. 1, 3 D.
4, 0
Q36. Which of the
following species has tetrahedral geometry?
A. BH4 – B. NH2 –
C. CO3 2– D.
H3O +
Q37. Number of π
bonds and σ bonds in the following structure is–
A. 6, 19 B. 4,
20
C. 5, 19 D. 5,
20
Q38. Which
molecule/ion out of the following does not contain unpaired electrons?
A. N2 +
B.
O2
C. O2 2–
D.
B2
Q39. Which of the
following options represents the correct bond order :
A. O2 –
> O2 > O2 +
B. O2 – < O2 < O2 +
C. O2 –
> O2 < O2 + D. O2 – < O2 > O2 +
Q40. The electronic
configuration of the outer most shell of the most electronegative element is
A. 2s22p5 B. 3s23p5
C. 4s24p5 D. 5s25p5
Q41. Which of the
following statements are not correct?
A. NaCl being an ionic compound is a good conductor of
electricity in the solid state.
B. In canonical
structures there is a difference in the arrangement of atoms.
C. Hybrid orbitals
form stronger bonds than pure orbitals.
D. VSEPR Theory can
explain the square planar geometry of XeF4 .we
Q42. Match the species in Column I with the
geometry/shape in Column II.
Column I Column
II
A. H3O
+
(a) Linear
B. HC ≡ CH (b)
Angular
C. ClO2
– (c)
Tetrahedral
D. NH4
+ (d)
Trigonal bipyramidal
(e) Pyramidal
Q43. Match the
species in Column I with the bond order in Column II.
Column I Column
II
A. NO (a)
1.5
B. CO
(b) 2.0
C. O2
–
(c) 2.5
D. O2
(d)
3.0
Q44. Match the items
given in Column I with examples given in Column II.
Column I Column
II
A. Hydrogen bond (a) C
B. Resonance
(b)
LiF
C. Ionic
solid (c)
H2
D. Covalent solid (d) HF
(e)
O3
Q45. Match the shape of molecules in Column I
with the type of hybridisation in Column II.
Column I
Column II
A.
Tetrahedral (a)
sp2
B. Trigonal (b)
sp
C. Linear (c)
sp3
Q46. Assertion (A)
: Though the central atom of both NH3 and H2O molecules
are sp3 hybridised, yet H–N–H bond angle is greater than that of
H–O–H.
Reason (R) :
This is because nitrogen atom has one lone pair and oxygen atom has two lone
pairs.
(A) A and R both are
correct, and R is the correct explanation of A.
(B) A and R both are correct, but R is not the correct explanation
of A.
(C) A is true but R is false.
(D) A and R both are
false.
Q47. Assertion (A): Among the two O–H bonds
in H2O molecule, the energy required to break the first O–H bond and
the other O–H bond is the same.
Reason (R) :
This is because the electronic environment around oxygen is the same even after
breakage of one O–H bond.
(A) A and R both are correct, and R is correct explanation
of A.
(B) A and R both are correct, but R is not the correct
explanation of A.
(C) A is true but R
is false.
(D) A and R both are false.
Q48.On converting 25
°C, 38 °C and 66 °C to kelvin scale, the correct answer will be (A) 298 K,
311 K and 339 K (B) 298 K,
300 K and 338 K
(C) 273 K, 278 K and 543 K (D)
298 K, 310 K and 338 K
Q49. Choose the
correct statement of the following
(A) conversion of solid into vapours without passing through
the liquid state is called vapourisation.
(B) conversion of vapours into solid without passing through
the liquid state is called sublimation.
(C) conversion of vapours into solid without passing through
the liquid state is called freezing.
(D) conversion of solid into liquid is called sublimation.
Q50. Rusting of an
article made up of iron is called
(A) corrosion and it is a physical as well as chemical change
(B) dissolution and it is a physical change
(C) corrosion and it is a chemical change
(D) dissolution and it is a chemical change
question paper is good to do the whole chapters revision in the form of test.
ReplyDeleteits easy and mind testing